18y^2=234

Solution for 18y^2=234 equation:

18y^2=234

We move all terms to the left:

18y^2-(234)=0

a = 18; b = 0; c = -234;
Δ = b2-4ac
Δ = 02-4·18·(-234)
Δ = 16848
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16848}=\sqrt{1296*13}=\sqrt{1296}*\sqrt{13}=36\sqrt{13}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36\sqrt{13}}{2*18}=\frac{0-36\sqrt{13}}{36}
=-\frac{36\sqrt{13}}{36}
=-\sqrt{13}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36\sqrt{13}}{2*18}=\frac{0+36\sqrt{13}}{36}
=\frac{36\sqrt{13}}{36}
=\sqrt{13}
$